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2πvr = ¼4πv²
cos∆ = ¼4πv²
cos∆ = ¼4
2cos∆ = 1
cos∆ = ½
∆ =
2πvr(1-cosL)=¼4πv²#
2(1-cosL) = L
2-2cosL = 1
2-1 = 2cosL # 1 = cosL
l=(cos=½)
[1] Al Chiaris. P. Angelo Secchi
Dirett.e dell'osserv.o

Coll.o Romano

  1. Alia manu: figura.